Solution unit 2 task 4

dp=βpodT = 1 273.15 K 1013.25 hPa 60 K =222.57 hPa
or when differentiating p=ρ RdT we yield
dp=d(ρRdT)=RdT dρ+ρRddT =0+1.29kg/m3287 J/kg 60 K = 222.14 hPa
The pressure does not raise this much because there is exchange with the environment.